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1. A vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?





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  • By: guest on 01 Jun 2017 05.44 pm
    Suppose the vessel initially contains 8 litres of liquid. Let x litres of this liquid be replaced with water. Quantity of water in new mixture = 3 - 3x + x litres 8 Quantity of syrup in new mixture = 5 - 5x litres 8 3 - 3x + x = 5 - 5x 8 8 5x + 24 = 40 - 5x 10x = 16 x = 8 . 5 So, part of the mixture replaced = 8 x 1 = 1 . 5 8 5
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