Axis ?->(Show Answer!)

1. Axis

Answer: Axes

Tags

Show Similar Question And Answers

QA->What is a graph is plotted taking °C along the Y-axis and of K along the X-axis?....

QA->If a graph is plotted taking the temperature in Fahrenheit along the Y-axis and the corresponding temperature in Celsius along X- axis it will be the straight line?....

QA->Which was the first Axis Power to surrender in the First World War?....

QA->Axis powers during World War II consisted of ?....

QA->Japan surrendered before the Axis Powers on ?....

MCQ->According to parallel axis theorem, the moment of inertia of a section about an axis parallel to the axis through centre of gravity (i.e. IP) is given by(where, A = Area of the section, IG = Moment of inertia of the section about an axis passing through its C.G., and h = Distance between C.G. and the parallel axis.)...

MCQ->In order to have a connecting rod equally strong in buckling about X-axis and Y-axis, the moment of inertia about X-axis should be __________ the moment of inertia about Y-axis....

MCQ->xx, x1 x1 and x2 x2 are parallel axes of which XX is the centroidal axis. If moment of inertia of the figure about x1 x1 axis is 10m4, what is the moment of inertia of the figure about x2 x2 axis? ...

MCQ->Assertion (A): The part of root locus on the real axis is not dependent on the poles and zeros which are not on the real axis.Reason (R): Poles and zeros which are not on the real axis occur in conjugate pairs

MCQ->Consider the following statements about root locus The intersection of root locus branches with the imaginary axis can be determined by the use of Routh criterionSegments of real axis having an odd number of real axis open loop poles plus zeros to their right are not parts of root locusThe number of root locus branches terminating on infinity is always zero Which of the above statements are correct?...

Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions Question ANSWER With Solution