Question Set

1. Boys will be boys means:





Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

Show Similar Question And Answers
QA->he average weight of 16 boys in a class is 25 kg and that of the remaining 8 boys is 15 kg. Find the average weights of all the boys in the class.....
QA->If + means × , - means † , × means - and † means + then 16 – 4 + 3 × 5 ÷ 2 =....
QA->In a certain code 743 means Mangoes are good; 657 means Eat good food; and 934 means Mangoes are ripe. Which digit means ripe in that language?....
QA->If ‘+’ means ‘×’, ‘__‘ means ‘+’, ‘×’ means ‘÷’ and ‘÷’ means ‘__‘ then find the value of; 6 – 9 + 8 × 3 ÷ 20 = ……. .....
QA->If + means , x means -, means + and - means x. Find 168x6-2+12?....
MCQ->Question: What is the code for 'or' in the code language? Statements: 'nik sa te' means 'right or wrong', 'ro da nik' means 'he is right' and 'fe te ro' means 'that is wrong'. 'pa nik la' means 'that right man', 'sa ne pa' means 'this or that' and 'ne ka re' means 'tell this there'.

....
MCQ->The average weight of 16 boys in a class is 50.25 kg and that of the remaining 8 boys is 45.15 kg. Find the average weights of all the boys in the class.....
MCQ->If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days, the time taken by 15 men and 20 boys in doing the same type of work will be:....
MCQ->Statements: Most teachers are boys. Some boys are students. Conclusions: Some students are boys. Some teachers are students.

....
MCQ->In a class of 60 students, the number of boys and girls participating in the annual sports is in the ratio 3 : 2 respectively. The number of girls not participating in the sports is 5 more than the number of boys not participating in the sports. If the number of boys participating in the sports is 15, then how many girls are there in the class ?....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution