1. The commonly used base for iron and steel work, is





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QA->P and Q can do a work in 30 days. Q and R can do the same work in 24 days and R and P in 20 days. They started the work together, but Q and R left after 10 days. How many days more will P take to finish the work?....
QA->P and Q can complete a work in 15 days and 10 days respectively. They started the work together and then Q left after 2 days. P alone completed the remaining work. The work was finished in --- days.....
QA->P and Q can complete a work in 20 days and 12 days respectively. P alone started the work and Q joined him after 4 days till the completion of the work. How long did the work last?....
QA->P can do a work in 24 days. Q can do the same work in 9 days and R can do the same in 12 days. Q and R start the work and leave after 3 days. P finishes the remaining work in --- days.....
QA->P can do a work in the same time in which Q and R together can do it. If P and Q work together, the work can be completed in 10 days. R alone needs 50 days to complete the same work. then Q alone can do it in....
MCQ->What will be the output of the following program? #include<iostream.h> class Base { int x, y; public: Base() { x = y = 0; } Base(int xx) { x = xx; } Base(int p, int q = 10) { x = p + q; y = q; } void Display(void) { cout<< x << " " << y << endl; } }objDefault(1, 1); class Derived: public Base { Base obj; public: Derived(int xx, int yy): Base(xx, xx + 1) { } Derived(Base objB = objDefault) { } }; int main() { Derived objD(5, 3); Derived ptrD = new Derived(objD); ptrD->Display(); delete ptrD; return 0; }....
MCQ->Consider the following statements about conditions that make a metal semiconductor contact rectifying N type semiconductor with work function φs more than work function φM of metalN type semiconductor with work function φs less than work function φM of metalP type semiconductor with work function φs more than work function φM of metalP type semiconductor with work function φs less than work function φM of metal. Of these statements....
MCQ->What will be the output of the following program? #include<iostream.h> class Base { public: int S, A, M; Base(int x, int y) { S = y - y; A = x + x; M = x x; } Base(int, int y = 'A', int z = 'B') { S = y; A = y + 1 - 1; M = z - 1; } void Display(void) { cout<< S << " " << A << " " << M << endl; } }; class Derived : public Base { int x, y, z; public: Derived(int xx = 65, int yy = 66, int zz = 67): Base(x) { x = xx; y = yy; z = zz; } void Display(int n) { if(n) Base::Display(); else cout<< x << " " << y << " " << z << endl; } }; int main() { Derived objDev; objDev.Display(-1); return 0; }....
MCQ->What will be the output of the following program? #include<iostream.h> class Base { public: char S, A, M; Base(char x, char y) { S = y - y; A = x + x; M = x x; } Base(char, char y = 'A', char z = 'B') { S = y; A = y + 1 - 1; M = z - 1; } void Display(void) { cout<< S << " " << A << " " << M << endl; } }; class Derived : public Base { char x, y, z; public: Derived(char xx = 65, char yy = 66, char zz = 65): Base(x) { x = xx; y = yy; z = zz; } void Display(int n) { if(n) Base::Display(); else cout<< x << " " << y << " " << z << endl; } }; int main() { Derived objDev; objDev.Display(0-1); return 0; }....
MCQ->interface Base { boolean m1 (); byte m2(short s); } which two code fragments will compile? interface Base2 implements Base {} abstract class Class2 extends Base { public boolean m1(){ return true; }} abstract class Class2 implements Base {} abstract class Class2 implements Base { public boolean m1(){ return (7 > 4); }} abstract class Class2 implements Base { protected boolean m1(){ return (5 > 7) }}....
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