What happens if the base and derived class contains definition of a function with same prototype? ?->(Show Answer!)

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1. What happens if the base and derived class contains definition of a function with same prototype?

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MCQ->What will be the output of the following program? #include<iostream.h> class Base { public: char S, A, M; Base(char x, char y) { S = y - y; A = x + x; M = x x; } Base(char, char y = 'A', char z = 'B') { S = y; A = y + 1 - 1; M = z - 1; } void Display(void) { cout<< S << " " << A << " " << M << endl; } }; class Derived : public Base { char x, y, z; public: Derived(char xx = 65, char yy = 66, char zz = 65): Base(x) { x = xx; y = yy; z = zz; } void Display(int n) { if(n) Base::Display(); else cout<< x << " " << y << " " << z << endl; } }; int main() { Derived objDev; objDev.Display(0-1); return 0; }....

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