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A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed: ?->(Show Answer!)
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1. A fires 5 shots to B's 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:





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  • By: guest on 01 Jun 2017 05.48 pm
    Let the total number of shots be x. Then, Shots fired by A = 5 x 8 Shots fired by B = 3 x 8 Killing shots by A = 1 of 5 x = 5 x 3 8 24 Shots missed by B = 1 of 3 x = 3 x 2 8 16 3x = 27 or x = 27 x 16 = 144. 16 3 Birds killed by A = 5x = 5 x 144 = 30. 24 24
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