1. xb (b + c - a) . xc (c + a - b) . xa (a + b - c) = ? xc xa xb
Ask Your Doubts Here
Comments
By: guest on 01 Jun 2017 05.49 pm
Given Exp. = x(b - c)(b + c - a) . x(c - a)(c + a - b) . x(a - b)(a + b - c) = x(b - c)(b + c) - a(b - c) . x(c - a)(c + a) - b(c - a) . x(a - b)(a + b) - c(a - b) = x(b2 - c2 + c2 - a2 + a2 - b2) . x-a(b - c) - b(c - a) - c(a - b) = (x0 x x0) = (1 x 1) = 1.
. x(a - b)(a + b) - c(a - b) = x(b2 - c2 + c2 - a2 + a2 - b2) . x-a(b - c) - b(c - a) - c(a - b) = (x0 x x0) = (1 x 1) = 1.