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1. For the circuit, let us assume that R = 1 Ω, L = 10-3 H, and V(t) = 10 cos (1000t + 30°)V and the differential equation for I(t) is given by




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  • By: guest on 02 Jun 2017 12.55 am
    Replacing current and voltage by their phasors I and 10ejp /b, resp. and by jω = j1000, we obtain the phasor equation I + 10-3(j1000I ) = 10ejp /6 or I (1 + j1) = 10ejp /6 Having determined the value of I , we now find the required solution to be I(t) = Rc [I ejωt] = Rc[7.07e -jp /2 ej1000t] = 7.07 cos (1000t - 15°)A.
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