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1. Which one is time invariant system?





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  • By: guest on 02 Jun 2017 01.13 am
    For time invariant system y(n, k) = y(n - k), where y(n, k) mean shift the input by n - k, while y(n - k) mean change all the n (a) y[n] = x[2n] ⇒ y(n, k) = x[2n - k] y(n - k) = x[2(n - k)] y(n, k) ≠ y(n - k) Time variant (b) y[n] = x[n] x[n - 1] y[n, k] = x[n - k] x[n - k - 1] y[n - k] = x[n - k] x[n - k - 1] y[n, k] = x[n - k] Time Invariant (c) y[n] = x[n/2] ⇒ y[n, k] ⇒ y[n - k] y[n, k] ≠ y[n - k] Time variant.
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