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1. Which two are equal? 32/4 (8 >> 2) << 4 2^5 128 >>> 2 2 >> 5





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  • By: guest on 02 Jun 2017 01.26 am
    (2) and (4) are correct. (2) and (4) both evaluate to 32. (2) is shifting bits right then left using the signed bit shifters >> and <<. (4) is shifting bits using the unsigned operator >>>, but since the beginning number is positive the sign is maintained. (1) evaluates to 8, (3) looks like 2 to the 5th power, but ^ is the Exclusive OR operator so (3) evaluates to 7. (5) evaluates to 0 (2 >> 5 is not 2 to the 5th).
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