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1. What will be the output of the program? class s1 implements Runnable { int x = 0, y = 0; int addX() {x++; return x;} int addY() {y++; return y;} public void run() { for(int i = 0; i < 10; i++) System.out.println(addX() + " " + addY()); } public static void main(String args[]) { s1 run1 = new s1(); s1 run2 = new s1(); Thread t1 = new Thread(run1); Thread t2 = new Thread(run2); t1.start(); t2.start(); } }





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  • By: guest on 02 Jun 2017 01.26 am
    Both threads are operating on different sets of instance variables. If you modify the code of the run() method to print the thread name it will help to clarify the output: public void run()
    {
    for(int i = 0; i < 10; i++)

    System.out.println(
    Thread.currentThread().getName() + ": " + addX() + " " + addY()
    );

    }
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