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1. For no tension condition in the base of a short column of circular section, the line of action of the load should be within a circle of diameter equal to __________ of the main circle.





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MCQ->For no tension condition in the base of a short column of circular section, the line of action of the load should be within a circle of diameter equal to __________ of the main circle.....
MCQ->What will be the output of the program? public class WrapTest { public static void main(String [] args) { int result = 0; short s = 42; Long x = new Long("42"); Long y = new Long(42); Short z = new Short("42"); Short x2 = new Short(s); Integer y2 = new Integer("42"); Integer z2 = new Integer(42); if (x == y) / Line 13 / result = 1; if (x.equals(y) ) / Line 15 / result = result + 10; if (x.equals(z) ) / Line 17 / result = result + 100; if (x.equals(x2) ) / Line 19 / result = result + 1000; if (x.equals(z2) ) / Line 21 / result = result + 10000; System.out.println("result = " + result); } }....
MCQ->If the stress on the cross-section of a circular short column of diameter D is to be wholly compressive, the load should be applied within a concentric circle of diameter....
MCQ->What will be the output of the following program? #include<iostream.h> class Base { int x, y; public: Base() { x = y = 0; } Base(int xx) { x = xx; } Base(int p, int q = 10) { x = p + q; y = q; } void Display(void) { cout<< x << " " << y << endl; } }objDefault(1, 1); class Derived: public Base { Base obj; public: Derived(int xx, int yy): Base(xx, xx + 1) { } Derived(Base objB = objDefault) { } }; int main() { Derived objD(5, 3); Derived ptrD = new Derived(objD); ptrD->Display(); delete ptrD; return 0; }....
MCQ->A short column of external diameter D1 and internal diameter D2 carries an external load W. For no-tension condition, the eccentricity will be :....
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