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What will be the output of the program? #include<stdio.h> #define CUBE(x) (xxx) int main() { int a, b=3; a = CUBE(b++); printf("%d, %d\n", a, b); return 0; } ?->(Show Answer!)
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1. What will be the output of the program? #include<stdio.h> #define CUBE(x) (xxx) int main() { int a, b=3; a = CUBE(b++); printf("%d, %d\n", a, b); return 0; }





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  • By: guest on 01 Jun 2017 06.00 pm
    The macro function CUBE(x) (x*x*x) calculates the cubic value of given number(Eg: 103.) Step 1: int a, b=3; The variable a and b are declared as an integer type and varaible b id initialized to 3. Step 2: a = CUBE(b++); becomes => a = b++ * b++ * b++; => a = 3 * 3 * 3; Here we are using post-increement operator, so the 3 is not incremented in this statement. => a = 27; Here, 27 is store in the variable a. By the way, the value of variable b is incremented by 3. (ie: b=6) Step 3: printf("%d, %d\n", a, b); It prints the value of variable a and b. Hence the output of the program is 27, 6.
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