Warning: implode(): Invalid arguments passed in /www/wwwroot/jobquiz.info/mdiscuss.php on line 336 What will be the output of the program? #include<stdio.h> #define PRINT(int) printf("int=%d, ", int); int main() { int x=2, y=3, z=4; PRINT(x); PRINT(y); PRINT(z); return 0; } ?->(Show Answer!)
1. What will be the output of the program? #include<stdio.h> #define PRINT(int) printf("int=%d, ", int); int main() { int x=2, y=3, z=4; PRINT(x); PRINT(y); PRINT(z); return 0; }
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By: guest on 01 Jun 2017 06.00 pm
The macro PRINT(int) print("%d,", int); prints the given variable value in an integer format. Step 1: int x=2, y=3, z=4; The variable x, y, z are declared as an integer type and initialized to 2, 3, 4 respectively. Step 2: PRINT(x); becomes printf("int=%d,",x). Hence it prints 'int=2'. Step 3: PRINT(y); becomes printf("int=%d,",y). Hence it prints 'int=3'. Step 4: PRINT(z); becomes printf("int=%d,",z). Hence it prints 'int=4'. Hence the output of the program is int=2, int=3, int=4.