1. What will be the output of the program? #include<stdio.h> int main() { static int a[20]; int i = 0; a[i] = i ; printf("%d, %d, %d\n", a[0], a[1], i); return 0; }
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By: guest on 01 Jun 2017 06.01 pm
Step 1: static int a[20]; here variable a is declared as an integer type and static. If a variable is declared as static and it will be automatically initialized to value '0'(zero). Step 2: int i = 0; here vaiable i is declared as an integer type and initialized to '0'(zero). Step 3: a[i] = i ; becomes a[0] = 0; Step 4: printf("%d, %d, %d\n", a[0], a[1], i); Here a[0] = 0, a[1] = 0(because all staic variables are initialized to '0') and i = 0. Step 4: Hence the output is "0, 0, 0".
Step 3: a[i] = i ; becomes a[0] = 0;
Step 4: printf("%d, %d, %d\n", a[0], a[1], i);
Here a[0] = 0, a[1] = 0(because all staic variables are initialized to '0') and i = 0.
Step 4: Hence the output is "0, 0, 0".