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What will be the output of the program? #include<stdio.h> int main() { int x=55; printf("%d, %d, %d\n", x<=55, x=40, x>=10); return 0; } ?->(Show Answer!)
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1. What will be the output of the program? #include<stdio.h> int main() { int x=55; printf("%d, %d, %d\n", x<=55, x=40, x>=10); return 0; }





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  • By: guest on 01 Jun 2017 06.01 pm
    Step 1: int x=55; here variable x is declared as an integer type and initialized to '55'.
    Step 2: printf("%d, %d, %d\n", x<=55, x=40, x>=10);
    In printf the execution of expressions is from Right to Left.
    here x>=10 returns TRUE hence it prints '1'.
    x=40 here x is assigned to 40 Hence it prints '40'.
    x<=55 returns TRUE. hence it prints '1'.
    Step 3: Hence the output is "1, 40, 1".
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