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What will be the output of the program? #include<stdio.h> int main() { char ch; ch = 'A'; printf("The letter is"); printf("%c", ch >= 'A' && ch <= 'Z' ? ch + 'a' - 'A':ch); printf("Now the letter is"); printf("%c\n", ch >= 'A' ?->(Show Answer!)
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1. What will be the output of the program? #include<stdio.h> int main() { char ch; ch = 'A'; printf("The letter is"); printf("%c", ch >= 'A' && ch <= 'Z' ? ch + 'a' - 'A':ch); printf("Now the letter is"); printf("%c\n", ch >= 'A' && ch <= 'Z' ? ch : ch + 'a' - 'A'); return 0; }




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  • By: guest on 01 Jun 2017 06.01 pm
    Step 1: char ch; ch = 'A'; here variable ch is declared as an character type an initialized to 'A'. Step 2: printf("The letter is"); It prints "The letter is". Step 3: printf("%c", ch >= 'A' && ch <= 'Z' ? ch + 'a' - 'A':ch); The ASCII value of 'A' is 65 and 'a' is 97. Here => ('A' >= 'A' && 'A' <= 'Z') ? (A + 'a' - 'A'):('A') => (TRUE && TRUE) ? (65 + 97 - 65) : ('A') => (TRUE) ? (97): ('A') In printf the format specifier is '%c'. Hence prints 97 as 'a'. Step 4: printf("Now the letter is"); It prints "Now the letter is". Step 5: printf("%c\n", ch >= 'A' && ch <= 'Z' ? ch : ch + 'a' - 'A'); Here => ('A' >= 'A' && 'A' <= 'Z') ? ('A') : (A + 'a' - 'A') => (TRUE && TRUE) ? ('A') :(65 + 97 - 65) => (TRUE) ? ('A') : (97) It prints 'A' Hence the output is The letter is a
    Now the letter is A
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