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What will be the output of the program ? #include<stdio.h> int main() { int k=1; printf("%d == 1 is" "%s\n", k, k==1?"TRUE":"FALSE"); return 0; } ?->(Show Answer!)
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1. What will be the output of the program ? #include<stdio.h> int main() { int k=1; printf("%d == 1 is" "%s\n", k, k==1?"TRUE":"FALSE"); return 0; }





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  • By: guest on 01 Jun 2017 06.01 pm
    Step 1: int k=1; The variable k is declared as an integer type and initialized to '1'. Step 2: printf("%d == 1 is" "%s\n", k, k==1?"TRUE":"FALSE"); becomes => k==1?"TRUE":"FALSE" => 1==1?"TRUE":"FALSE" => "TRUE" Therefore the output of the program is 1 == 1 is TRUE
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