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What will be the output of the program ? #include<stdio.h> int main() { char p[] = "%d\n"; p[1] = 'c'; printf(p, 65); return 0; } ?->(Show Answer!)
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1. What will be the output of the program ? #include<stdio.h> int main() { char p[] = "%d\n"; p[1] = 'c'; printf(p, 65); return 0; }




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  • By: guest on 01 Jun 2017 06.02 pm
    Step 1: char p[] = "%d\n"; The variable p is declared as an array of characters and initialized with string "%d". Step 2: p[1] = 'c'; Here, we overwrite the second element of array p by 'c'. So array p becomes "%c". Step 3: printf(p, 65); becomes printf("%c", 65); Therefore it prints the ASCII value of 65. The output is 'A'.
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