Warning: implode(): Invalid arguments passed in /www/wwwroot/jobquiz.info/mdiscuss.php on line 336 What will be the output of the program ? #include<stdio.h> int main() { int i; char a[] = "\0"; if(printf("%s", a)) printf("The string is not empty\n"); else printf("The string is empty\n"); return 0; } ?->(Show Answer!)
1. What will be the output of the program ? #include<stdio.h> int main() { int i; char a[] = "\0"; if(printf("%s", a)) printf("The string is not empty\n"); else printf("The string is empty\n"); return 0; }
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By: guest on 01 Jun 2017 06.02 pm
The function printf() returns the number of charecters printed on the console. Step 1: char a[] = '\0'; The variable a is declared as an array of characters and it initialized with "\0". It denotes that the string is empty. Step 2: if(printf("%s", a)) The printf() statement does not print anything, so it returns '0'(zero). Hence the if condition is failed. In the else part it prints "The string is empty".