What will be the output of the program ? #include<stdio.h> int main() { union a { int i; char ch[2]; }; union a u; u.ch[0]=3; u.ch[1]=2; printf("%d, %d, %d\n", u.ch[0], u.ch[1], u.i); return 0; } ?->(Show Answer!)

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1. What will be the output of the program ? #include<stdio.h> int main() { union a { int i; char ch[2]; }; union a u; u.ch[0]=3; u.ch[1]=2; printf("%d, %d, %d\n", u.ch[0], u.ch[1], u.i); return 0; }

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By: guest on 01 Jun 2017 06.02 pm

The system will allocate 2 bytes for the union. The statements u.ch[0]=3; u.ch[1]=2; store data in memory as given below.

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