49501. Sine wave A has a positive-going zero crossing at 45°. Sine wave B has a positive-going zero crossing at 60°. Which of the following statements is true?

49502. A phasor represents

49503. A sine wave with a period of 4 ms is changing at a faster rate than a sine wave with a period of

49504. A waveform has a baseline of 3 V, a duty cycle of 20%, and an amplitude of 8 V. The average voltage value is

49505. A sine wave with an rms value of 12 V is riding on a dc level of 18 V. The maximum value of the resulting waveform is

49506. If the rms current through a 6.8 k resistor is 8 mA, the rms voltage drop across the resistor is

49507. The average half-cycle value of a sine wave with a 40 V peak is

49508. The duty cycle of a pulse waveform with a pulse width of 10 µs and a period of 100 µs is 25%.

49509. The angular position of a phasor represents the angle of the sine wave with respect to a reference.

49510. The designation rms means repetitions measured per second.

49511. The unit of frequency is the hertz.

49512. Average value of a sine wave is 0.707 times the peak value.

49513. The length of a phasor represents the amplitude.

49514. A ramp is the type of waveform characterized by a non-linear increase or decrease in voltage or current.

49515. The instantaneous value is the voltage or current value of a waveform at its peak.

49516. Duty cycle is the characteristic of a pulse waveform that indicates the high time versus the low time.

49517. Periodic is characterized by a repetition at fixed time intervals.

49518. Amplitude is the maximum value of a voltage or current.

49519. A 1 kHz signal has a period of 1 ms.

49520. If the rms voltage drop across a 15 k resistor is 16 V, the peak current through the resistor is

49521. The conductive loop on the rotor of a simple two-pole, single-phase generator rotates at a rate of 400 rps. The frequency of the induced output voltage is

49522. How many degrees are there in /3 rad?

49523. To produce an 800 Hz sine wave, a four-pole generator must be operated at

49524. One sine wave has a positive-going zero crossing at 15° and another sine wave has a positive-going zero crossing at 55°. The phase angle between the two waveforms is

49525. Who of the following was the lady representive of India at the Second Round Table Conference?

49526. Jinnah declared which day as”Direct Action Day”:

49527. Who was the Chairman of the Partition Council?

49528. During the Civil Disobedience movement,who led the ‘Red Shirts’of North-Western India?

49529. In which year Sree Narayana Guru held an Ali Religious Conference at Advaitasram,Aluva?

49530. What is the voltage drop across R1?

49531. What is the voltage drop across R2?

49532. In assigning the direction of branch currents,

49533. Find I1. 4I1 + 4I2 = 2
6I1 + 7I2 = 4

49534. Using the mesh current method, find the branch current, IR1, in the above figure.

49535. What is the current through R2?

49536. The first row of a certain determinant has the numbers 3 and 5. The second row has the numbers 7 and 2. The value of this determinant is

49537. The first row of a certain determinant has the numbers 10 and 6. The second row has the numbers 3 and 5. The value of this determinant is

49538. What is the voltage drop across R3?

49539. The expansion method for evaluating determinants is

49540. Which of the following are known as Brettonwood twins?

49541. The node voltage method is based on Kirchhoff's voltage law.

49542. A loop current is an actual current in a branch.

49543. The mesh current method is based on Kirchhoff's current law.

49544. The branch current method is based on Kirchhoff's voltage law and Kirchhoff's current law.

49545. When assigning branch currents, you need not be concerned with the direction you choose.

49546. Generally, the mesh current method results in fewer equations than the node voltage method.

49547. Third-order determinants are evaluated by the expansion method or by the cofactor method.

49548. Second-order determinants are evaluated by subtracting the signed cross-products.

49549. The mesh method can be applied to circuits with any number of loops.