1. India govt plan to construct new corridor for high speed train with speed range 300-350 kmph. What is the present maximum speed of long distance train in India?

Answer: 100-120 kmph

Reply

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

Show Similar Question And Answers
QA->India govt plan to construct new corridor for high speed train with speed range 300-350 kmph. What is the present maximum speed of long distance train in India?....
QA->A train 300m long crossed a platform 900m long in 1 minute 12 seconds. Find the speed of the train in km/hr....
QA->Distance between two stations A and B is 778 km. A train covers the journey from A to B at 84 km per hour and returns back to A with a uniform speed of 56km per hour. Find the average speed of the train during the whole journey?....
QA->A train 110ms long passes a telegraph pole in 3 seconds. How long will it take to cross railway platform 165 ms long....
QA->A train 300 m long is running with a speed of 54 km/hr. In what time will it cross a telephone post?....
MCQ->India govt plan to construct new corridor for high speed train with speed range 300-350 kmph.What is the present maximum speed of long distance train in India?...
MCQ->A train 120 metres long running at 25 kmph is overtaken by another train of length 80 metres running at 40 kmph in the same direction along a parallel line.How long will the faster train take to completely overtake the slower train?...
MCQ->A 270 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train?...
MCQ->A man who undertakes a journey covers one third of his journey at a speed of 60 kmph and the next one third at 30 kmph and the next one third at 30 kmph and the last part at 10 kmph.What is the average speed of his journey?...
MCQ->What will be the output of the program? public class WrapTest { public static void main(String [] args) { int result = 0; short s = 42; Long x = new Long("42"); Long y = new Long(42); Short z = new Short("42"); Short x2 = new Short(s); Integer y2 = new Integer("42"); Integer z2 = new Integer(42); if (x == y) / Line 13 / result = 1; if (x.equals(y) ) / Line 15 / result = result + 10; if (x.equals(z) ) / Line 17 / result = result + 100; if (x.equals(x2) ) / Line 19 / result = result + 1000; if (x.equals(z2) ) / Line 21 / result = result + 10000; System.out.println("result = " + result); } }...
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution