Question Set

1. In the case of a centrifugal pump,the kinetic energy per unit weight of water is found to be 8 Nm and the work done per unit weight of water was 24 Nm.So the percentage of work converted into kinetic energy will be:





Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

Show Similar Question And Answers
QA->The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, what is the weight of B?....
QA->P and Q can do a work in 30 days. Q and R can do the same work in 24 days and R and P in 20 days. They started the work together, but Q and R left after 10 days. How many days more will P take to finish the work?....
QA->In nuclear fission; how many percentage of mass is converted into energy?....
QA->In nuclear fission, how many percentage of mass is converted into energy?....
QA->In nuclear fission, the percentage of mass converted into energy is about?....
MCQ->In the case of a centrifugal pump,the kinetic energy per unit weight of water is found to be 8 Nm and the work done per unit weight of water was 24 Nm.So the percentage of work converted into kinetic energy will be:....
MCQ->What will be the output of the C#.NET code snippet given below? char ch = Convert.ToChar ('a' | 'b' | 'c'); switch (ch) { case 'A': case 'a': Console.WriteLine ("case A | case a"); break; case 'B': case 'b': Console.WriteLine ("case B | case b"); break; case 'C': case 'c': case 'D': case 'd': Console.WriteLine ("case D | case d"); break; }....
MCQ->In the casing of a centrifugal pump, the kinetic energy of the water is converted into pressure energy before the water leaves the casing.....
MCQ->Consider the following statements associated with the laws of weights in the theory of erros : 1. If an equation is multiplied by its own weight, then the weight of the resulting equation is equal to the reciprocal of the weight of the equation. 2. The weight of the algebraic sum of two or more quantities is equal to the reciprocal of the sum of the individual weights. 3. If the quantity of a given weight is multiplied by a factor, then the weight of the result is obtained by dividing its given weight by the square root of that factor. 4. If the quantity of a given weight is divided by a factor, then the weight of the result is obtained by multiplying its given weight by the square of that factor. Of these statements :....
MCQ->A centrifugal pump designed to pump water is employed to pump a more viscous oil. In the later case, the pump....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution