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FeO (s) + CO (g) = Fe (s) + CO2 (g), k = 0. 435 at 1173E; At equilibrium, what will be the number of moles of CO gas required to reduce one mole of FeO at 1173 K? ?->(Show Answer!)
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1. FeO (s) + CO (g) = Fe (s) + CO2 (g), k = 0. 435 at 1173E; At equilibrium, what will be the number of moles of CO gas required to reduce one mole of FeO at 1173 K?





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