1. At standard conditions, N2 + 2O2 2NO2; ΔG° = 100 kJ/mole NO + O2 2NO2; ΔG° = -35 kJ/mole The standard free energy of formation of NO in kJ/mole is





Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

Show Similar Question And Answers
QA->Which is not helpful for delta formation?....
QA->An​ ​electrochemical​ ​cell​ ​which​ ​is​ ​used​ ​as​ ​a​ ​source​ ​of​ ​direct​ ​electrical current​ ​at​ constant​ ​voltage​ ​under​ ​standard​ ​conditions​ ​is​ ​called​ ​a:....
QA->The standard heat of formation of diamond is?....
QA->What is the net gain of energy from one gram mole of glucose during aerobic respiration?....
QA->Chemical mastication is operational after (deg. Centigrade)....
MCQ->At standard conditions, N2 + 2O2 2NO2; ΔG° = 100 kJ/mole NO + O2 2NO2; ΔG° = -35 kJ/mole The standard free energy of formation of NO in kJ/mole is....
MCQ->One mole of methane undergoes complete combustion in a stoichiometric amount of air. The reaction proceeds as CH4 + 2O2 → CO2 + 2H2O. Both the reactants and products are in gas phase. ΔH°298 = - 730 kJ/mole of methane. If the average specific heat of all the gases/vapour is 40 J/mole.K, the maximum temperature rise of the exhaust gases in °C would be approximately equal to....
MCQ->One mole of methane undergoes complete combustion in a stoichiometric amount of air. The reaction proceeds as CH4 + 2O2 → CO2 + 2H2O. Both the reactants and products are in gas phase. ΔH°298 = - 730 kJ/mole of methane. Mole fraction of water vapour in the product gases is about....
MCQ->If h1[n] = 3δ[n] + δ[n - 1], h2[n] = 2δ[n] + δ[n - 2] h3[n] = δ[n] - 3δ[n - 1] + 7δ[n - 4] + 6δ[n - 6] h[n] = h1[n] h2[n] + h3[n] h1[n] has value....
MCQ->The combustion equations of carbon and carbon monoxide are as follows: C + O2 = CO2, ΔH = - 394 kJ/kg . mole CO + 1/2 O2 = CO2, ΔH = - 284.5 kJ/kg. mole. The heat of formation of CO is __________ kJ/kg. mole.....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution