1. The general expression for the B.M. of a beam of length l is the beam carries





Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

Show Similar Question And Answers
QA->A short expression of general truth....
QA->A train moving with uniform speed passed a bridge of length 2000 metres in 2 ½ minutes.It took ½ minutes to pass a telephone post.What is the length of the train in metres?....
QA->The length and breadth of a rectangular field in the ratio of 12: 7 . Find the length if area of the field is 52,500 Sq.m?....
QA->A train of length 150 meters took 8 seconds to cross a bridge of length 250 meters. Time taken by the train to cross a telephone post is....
QA->The ratio of length and breadth of a rectangle is 7: if perimeter is 52 then, what is the length of the rectangle?....
MCQ->A simply supported beam 'A' of length l, breadth b and depth d carries a central load W. Another beam 'B' of the same dimensions carries a central load equal to 2 W. The deflection of beam 'B' will be __________ as that of beam 'A'.....
MCQ->A simply supported beam 'A' of length l, breadth b, and depth d carries a central point load W. Another beam 'B' has the same length and depth but its breadth is doubled. The deflection of beam 'B' will be __________ as compared to beam 'A'.....
MCQ->ABCD is a beam of length 5l which is supported at B and C (having supported length BC = 'l') and having two equal overhangs AB and CD of length 2l each. It carries a u.d.l. of intensity p per unit length throughout the beam as shown in the given figure. The points of contraflexure will occur ....
MCQ->The general expression for the B.M. of a beam of length l is the beam carries....
MCQ->A simply supported beam which carries a uniformly distributed load has two equal overhangs. To have maximum B.M. produced in the beam least possible, the ratio of the length of the overhang to the total length of the beam, is....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution