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1. From the following list of input conditions, determine the state of the five output leads on a 74148 octal-to-binary encoder. I0 = 1 I3 = 1 I6 = 1 I1 = 1 I4 = 0 I7 = 1 I2 = 1 I5 = 1 EI = 0





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MCQ->From the following list of input conditions, determine the state of the five output leads on a 74148 octal-to-binary encoder. I0 = 1 I3 = 1 I6 = 1 I1 = 1 I4 = 0 I7 = 1 I2 = 1 I5 = 1 EI = 0....
MCQ->When data input I1 of a 74148 octal-to-binary encoder is active, the data output is: A0 = 0 A1 = 0 A2 = 1

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MCQ->What will be the output of the program? #include<stdio.h> #include<stdarg.h> void fun1(char, int, int , float , char ); void fun2(char ch, ...); void (p1)(char, int, int , float , char ); void (p2)(char ch, ...); int main() { char ch='A'; int i=10; float f=3.14; char p="Hello"; p1=fun1; p2=fun2; (p1)(ch, i, &i, &f, p); (p2)(ch, i, &i, &f, p); return 0; } void fun1(char ch, int i, int pi, float pf, char p) { printf("%c %d %d %f %s \n", ch, i, pi, pf, p); } void fun2(char ch, ...) { int i, pi; float pf; char p; va_list list; printf("%c ", ch); va_start(list, ch); i = va_arg(list, int); printf("%d ", i); pi = va_arg(list, int); printf("%d ", pi); pf = va_arg(list, float); printf("%f ", pf); p = va_arg(list, char ); printf("%s", p); }....
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