An observer 1.6 m tall is 203 away from a tower. The angle of elevation from his eye to the top of the tower is 30?. The heights of the tower is: ?->(Show Answer!)

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An observer 1.6 m tall is 203 away from a tower. The angle of elevation from his eye to the top of the tower is 30?. The heights of the tower is: ?->(Show Answer!)

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1. An observer 1.6 m tall is 203 away from a tower. The angle of elevation from his eye to the top of the tower is 30?. The heights of the tower is:

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By: guest on 01 Jun 2017 05.46 pm

Let AB be the observer and CD be the tower. Draw BE CD. Then, CE = AB = 1.6 m, BE = AC = 203 m. DE = tan 30? = 1 BE 3 DE = 203 m = 20 m. 3 CD = CE + DE = (1.6 + 20) m = 21.6 m.

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