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1. If n is a natural number, then (6n2 + 6n) is always divisible by:
(A): 12 only
(B): 6 and 12 both
(C): 6 only
(D): by 18 only
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By: guest on 01 Jun 2017 05.46 pm
(6n2 + 6n) = 6n(n + 1), which is always divisible by 6 and 12 both, since n(n + 1) is always even.
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