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1. (12 + 22 + 32 + ... + 102) = ?





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  • By: guest on 01 Jun 2017 05.46 pm
    We know that (12 + 22 + 32 + ... + n2) = 1 n(n + 1)(2n + 1) 6 Putting n = 10, required sum = 1 x 10 x 11 x 21 = 385 6
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