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1. A number was divided successively in order by 4, 5 and 6. The remainders were respectively 2, 3 and 4. The number is:





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  • By: guest on 01 Jun 2017 05.46 pm
    4 | x z = 6 x 1 + 4 = 10 ----------- 5 | y -2 y = 5 x z + 3 = 5 x 10 + 3 = 53 ----------- 6 | z - 3 x = 4 x y + 2 = 4 x 53 + 2 = 214 ----------- | 1 - 4 Hence, required number = 214.
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