1. In figure base current is 10 μA and βdc = 100. Then VE =





Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

  • By: guest on 01 Jun 2017 11.43 pm
    IC = 1 mA and VCE = 20 - 5 x 103 x 1 x 10-3 = 15 V.
Show Similar Question And Answers
QA->A man is facing East, then the turns left and goes 10 m, then turns right and goes 5 m, then goes 5 m to the South and from there 5 m to West. In which direction is he, from his original place ?....
QA->A man who can swim 48 m/minute in still water. He swims 200 m against the current and 200 m with the current. If the difference between those two times is 10 minutes, what is the speed of the current?....
QA->A man who can swim 48 m/minute in still water. He swims 200 m against the current and 200 m with the current. If the difference between those two times is 10 minutes, what is the speed of the current?....
QA->John started from his home and walked 12 km.Then he took a right turn and walked 4 km.Then again,he took a right turn and walked 8 km and finally took another right turn and walked 1 km.How far is he from his home now?....
QA->Speed of a swimmer when moving in the direction perpendicular to the direction of the current is 16 km/h, speed of the current is 3 km/h. So the speed of the swimmer against the current will be (in km/h):....
MCQ->What will be the output of the following program? #include<iostream.h> class Base { int x, y; public: Base() { x = y = 0; } Base(int xx) { x = xx; } Base(int p, int q = 10) { x = p + q; y = q; } void Display(void) { cout<< x << " " << y << endl; } }objDefault(1, 1); class Derived: public Base { Base obj; public: Derived(int xx, int yy): Base(xx, xx + 1) { } Derived(Base objB = objDefault) { } }; int main() { Derived objD(5, 3); Derived ptrD = new Derived(objD); ptrD->Display(); delete ptrD; return 0; }....
MCQ->What will be the output of the following program? #include<iostream.h> class Base { public: int S, A, M; Base(int x, int y) { S = y - y; A = x + x; M = x x; } Base(int, int y = 'A', int z = 'B') { S = y; A = y + 1 - 1; M = z - 1; } void Display(void) { cout<< S << " " << A << " " << M << endl; } }; class Derived : public Base { int x, y, z; public: Derived(int xx = 65, int yy = 66, int zz = 67): Base(x) { x = xx; y = yy; z = zz; } void Display(int n) { if(n) Base::Display(); else cout<< x << " " << y << " " << z << endl; } }; int main() { Derived objDev; objDev.Display(-1); return 0; }....
MCQ->What will be the output of the following program? #include<iostream.h> class Base { public: char S, A, M; Base(char x, char y) { S = y - y; A = x + x; M = x x; } Base(char, char y = 'A', char z = 'B') { S = y; A = y + 1 - 1; M = z - 1; } void Display(void) { cout<< S << " " << A << " " << M << endl; } }; class Derived : public Base { char x, y, z; public: Derived(char xx = 65, char yy = 66, char zz = 65): Base(x) { x = xx; y = yy; z = zz; } void Display(int n) { if(n) Base::Display(); else cout<< x << " " << y << " " << z << endl; } }; int main() { Derived objDev; objDev.Display(0-1); return 0; }....
MCQ->interface Base { boolean m1 (); byte m2(short s); } which two code fragments will compile? interface Base2 implements Base {} abstract class Class2 extends Base { public boolean m1(){ return true; }} abstract class Class2 implements Base {} abstract class Class2 implements Base { public boolean m1(){ return (7 > 4); }} abstract class Class2 implements Base { protected boolean m1(){ return (5 > 7) }}....
MCQ->Match List-I with List-II and select the right answer using the code given below: List-I List-II (Current) (Feature) A. Kuroshio current 1. Warm current in Atlantic Ocean B. Peru 2. Cold current in the current Atlantic Ocean C. Labrador 3. Warm current in the current Pacific Ocean D. Florida current 4. Cold current in the Pacific Ocean Codes: A B C D?....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution