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1. Three analog signals, having bandwidths 1200 Hz, 600 Hz, 600 Hz are sampled at their Nyquist rates, encoded with 12 bit words, and time division multiplexed. The bit rate for the multiplexed signal is





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  • By: guest on 01 Jun 2017 11.48 pm
    The total message bandwidth = 1200 Hz + 600 Hz + 600 Hz = 2400 Hz Sampling frequency = 4800 samples/sec. Hence, Bit rate = 4800 x 12 57.6 kbps.
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