Question Set

1. 24 telephone channels, each band limited to 3.4 kHz are to be time division multiplexed using PCM. If sampling frequency is 10 kHz and number of quantization levels is 128, the required bandwidth of PCM is





Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

  • By: guest on 01 Jun 2017 11.48 pm
    Bandwidth ≈ 24 (ln2 128) 10 kHz = 1.68 MHz.
Show Similar Question And Answers
QA->Which of these methods involves passing paper through a press twice but using one same plate each time to print two complete signatures on each sheet ?....
QA->Two trains are 2 km apart and their lengths are 200 m and 300 m. They are approaching towards each other with a speed of 20 m/s and 30 m/s respectivety. after how much time they cross each other....
QA->The smallest number which if divided by 9,12, and 16, each time 5 remains. The number is _____....
QA->There are 50 students in a class. In a class test 22 students get 25 marks each, 18 students get 30 marks each. Each of the remaining gets 16 marks. The average mark of the whole class is :....
QA->What is the number in the place of ? in the sequence 3, 28, 128, 353, 753, ?....
MCQ->24 telephone channels, each band limited to 3.4 kHz are to be time division multiplexed using PCM. If sampling frequency is 10 kHz and number of quantization levels is 128, the required bandwidth of PCM is....
MCQ->24 telephone channels, each band limited to 3.4 kHz, are to be time division multiplexed by using PCM, calculate the bandwidth of PCM system for 128 quantization levels and an 8 KHz sampling frequency....
MCQ->Voice signal band limited to 3.4 KHz is sampled and pulse code modulated using 64 quantization levels. Ten such signals are time division multiplexed using one 5-bit synchronizing word every alternate frame. The minimum channel bandwidth required for transmission of the TDM signal is....
MCQ->24 telephone channels are frequency division multiplexed using an SSB modulation. Assuming 3 kHz per channel, the required band width is....
MCQ->A speech signal, band limited to 4kHz and peak voltage varying between + 5V and - 5V is sampled at the Nyquist rate. Each sample is quantized and represented by 8 bits. The number of quantization levels required to reduce the quantization noise by a factor of 4 would be....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution