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1. Three taps A, B and C can fill a tank in 12, 15 and 20 hours respectively. If A is open all the time and B and C are open for one hour each alternately, the tank will be full in:





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  • By: guest on 01 Jun 2017 05.47 pm
    (A + B)'s 1 hour's work = 1 + 1 = 9 = 3 . 12 15 60 20 (A + C)'s hour's work = 1 + 1 = 8 = 2 . 12 20 60 15 Part filled in 2 hrs = 3 + 2 = 17 . 20 15 60 Part filled in 6 hrs = 3 x 17 = 17 . 60 20 Remaining part = 1 - 17 = 3 . 20 20 Now, it is the turn of A and B and 3 part is filled by A and B in 1 hour. 20 Total time taken to fill the tank = (6 + 1) hrs = 7 hrs.
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