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1. The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is:
(A): 1008
(B): 1015
(C): 1022
(D): 1032
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By: guest on 01 Jun 2017 05.48 pm
Required number = (L.C.M. of 12,16, 18, 21, 28) + 7 = 1008 + 7 = 1015
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