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1. A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:

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By: guest on 01 Jun 2017 05.48 pm

Let the speed of the second train be x km/hr. Relative speed = (x + 50) km/hr = (x + 50) x 5 m/sec 18 = 250 + 5x m/sec. 18 Distance covered = (108 + 112) = 220 m. 220 = 6 250 + 5x 18 250 + 5x = 660 x = 82 km/hr.