1. Which of the following is λ/2 length?





Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

Show Similar Question And Answers
QA->A train moving with uniform speed passed a bridge of length 2000 metres in 2 ½ minutes.It took ½ minutes to pass a telephone post.What is the length of the train in metres?....
QA->The length and breadth of a rectangular field in the ratio of 12: 7 . Find the length if area of the field is 52,500 Sq.m?....
QA->A train of length 150 meters took 8 seconds to cross a bridge of length 250 meters. Time taken by the train to cross a telephone post is....
QA->The ratio of length and breadth of a rectangle is 7: if perimeter is 52 then, what is the length of the rectangle?....
QA->A train having a length of 240 metre passes a post in 24 seconds. How long will it take to pass a platform having a length of 650 metre?....
MCQ->If the energy radiated per second per sq. cm. of the surface for wave lengths lying between λ, and λ + dλ is represented by (eλ.dλ), then eλ is called....
MCQ->Consider the following; for a loss-less transmission line we can write, Zin = - jz0 for a shorted line with l = λ/8Zin = ± j ∞ for a shorted line with l = λ/4Zin= jz0 for an open line with l = λ/2Zin = 0 for a matched line of any length Select the correct answer using the codes given below codes.....
MCQ->If the characteristic equation is (λ + 1) (λ + 2) (λ + 3) = 0, the eigen values are....
MCQ->If Sample class has a Length property with get and set accessors then which of the following statements will work correctly? Sample.Length = 20; Sample m = new Sample(); m.Length = 10; Console.WriteLine(Sample.Length); Sample m = new Sample(); int len; len = m.Length; Sample m = new Sample(); m.Length = m.Length + 20;....
MCQ->The input impedance of short-circuited line of length l where λ/4 < l < λ/2, is....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution