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1. For the network shown below, determine fHi and fHO, if, r0 = ∞, Cbe = 36 Pf, Cbc = 4 Pf, Cce = 1 Pf, Cwo = 8 Pf, Cwi = 6 Pf where Cwo = wiring capacitance at output side, Cwi = wiring capacitance at input side





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  • By: guest on 02 Jun 2017 12.54 am
    Equivalent is RTi = RS || R1 || R2 || Ri = 0.531 KΩ Ci = Cwi + Cbe + (1 + AV)Cbc = 6pf + 36pf + (1 - c - 90) 4 pf = 460 pf RT2 = RC || RL = 4 K || 2.2 K = 1.419 KW C0 = Cwo + Cce + CMO
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