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1. Given f = GEF + KHIJ + LMON + TUV WXYZ and E + F + G = LMN V + W = U . Z . Y . X . T NAND B (UVW ⊕ WVU ) = KJ(XY ⊕ XY ) Then f is equivalent to





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  • By: guest on 02 Jun 2017 12.55 am
    (UVW ⊕ WVU ) = 1 = KJ(XY ⊕ XY ) ∴ KJ = 1 NAND B ∴ HI = 1 Since f = GEF + 1 + LMON + TUV WXYZ = 1.
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