1. A speech signal, band limited to 4kHz and peak voltage varying between + 5V and - 5V is sampled at the Nyquist rate. Each sample is quantized and represented by 8 bits. If the bits 0 and 1 are transmitted using bipolar pulses, the minimum bandwidth required for distortion free transmission is
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By: guest on 02 Jun 2017 12.55 am
According to Nyquist Criteria, minimum sampling frequency = 2 x 4 k = 8 kHz But each cycle can accommodate two bits Thus minimum frequency = 4 kHz.