1. In analog signal given below is sampled at such a rate that the samples of signal can be given to a collection of buffers having capacity of either 24 samples/sec. or 25 samples/sec. The sampling rate is minimum such that it fully utilizes the collection of both types of buffers m(t) = 2 sin 480p t + 3 sin 720 p t
The folding (maximum) frequency is
Ask Your Doubts Here
Comments
By: guest on 02 Jun 2017 12.56 am
LCM of 24 and 25 is 600 which will give maximum utilization of the buffers ∴ Sampling frequency is 600 ∴ Folding frequency = 600/2 = 300.