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1. For the network shown, determine z1 , z0 and Av





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  • By: guest on 02 Jun 2017 12.56 am
    = 24.04 μA IE = (1 + β)IB = 2.428 mA; = 10.7 Ω (i) zi = RB||Bre = = 0.937 K = 1.067 K (ii) Z0 = RC = 3 kΩ (iii) = -280.37 ∴ Zi = 1.067 KΩ; Z0 = 3 KΩ; Av = -280.37 .
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