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1. A hollow iron pipe is 21 cm long and its external diameter is 8 cm. If the thickness of the pipe is 1 cm and iron weighs 8 g/cm3, then the weight of the pipe is:





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  • By: guest on 01 Jun 2017 05.49 pm
    External radius = 4 cm, Internal radius = 3 cm. Volume of iron = 22 x [(4)2 - (3)2] x 21 cm3 7 = 22 x 7 x 1 x 21 cm3 7 = 462 cm3. Weight of iron = (462 x 8) gm = 3696 gm = 3.696 kg.
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