1. A specimen of metal has n valence electrons per m3. If vx is the average velocity of these electrons, each having a charge e, the current density J is




Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

Show Similar Question And Answers
QA->There are 50 students in a class. In a class test 22 students get 25 marks each, 18 students get 30 marks each. Each of the remaining gets 16 marks. The average mark of the whole class is :....
QA->The average of six numbers is x and the average of three of these is y. If the average of the remaining three is z, then....
QA->The captain of a cricket team of 11 members is 26 years old and the wicket keeper is 3 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. Find out the average age of the team.....
QA->A type of cyber crime that occurs in pay per click online advertising when a person, automated script or computer program imitates a legitimate user of a web browser clicking on an ad, for the purpose of generating a charge per click without having actual interest in the target of the ad’s link.....
QA->A type of cyber crime that occurs in pay per click online advertising when a person, automated script or computer program imitates a legitimate user of a web browser clicking on an ad, for the purpose of generating a charge per click without having actual interest in the target of the ad’s link.....
MCQ->A specimen of metal has n valence electrons per m3. If vx is the average velocity of these electrons, each having a charge e, the current density J is....
MCQ->Assertion (A): An electron having charge - e and mass m and lying in an electric field E is subjected to an acceleration - (e/m) E.Reason (R): If there are n electrons/m3 moving with velocity vx and each electron has a charge - e, the current density J = - n evx.

....
MCQ->Consider an arbitrary distribution of conducting bodies in a charge free space according to the uniqueness theorem, which of following are required to be specified in order that the field is uniquely determined everywhere? Total charge on each conductorPotential at each conductor surfacePotential at same of conductor and total charge on the remainderTotal charge as well as potential gradient on each conductor surface Select the correct answer using the codes given below codes....
MCQ->The simplest method of welding two pieces of metal together is known as pressure welding.The ends of a metal are heated to a white heat-for iron,the welding temperature should be about 1300C-in a flame.At this temperature the metal becomes plastic.The ends are pressed or hammered together,and the joint is smoothed off.Care must be taken to ensure that surfaces are thoroughly clean first,for dirt will weaken the weld.Moreover,the heating of iron or steel to a high temperature cause oxidation,and a film of oxide is added to the heated surfaces.For this reason,flux is applied to the heated metal.At welding heat,flux melts and the oxide particles are dissolved in it together with any other impurities which may be present.The metal surfaces are pressed together,and the flux is squeezed out from the center of the weld.A number of different types of weld may be used,but for fairly thick bars of metals,a vee-shaped belt should be normally employed.It is rather stronger than ordinary butt weld. The simplest way of welding two pieces of metal together is....
MCQ->A sphere with charge Q was placed in, but not touching a larger hollow sphere. If there is any charge initially on the outer sphere; to remove it the outer sphere was earthed momentarily, and then the inner sphere was removed. The charge remaining on the outer sphere was then measured. This charge was found to be __________ to the charge on the inner sphere.....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution