1. In figure, the voltage V1 = 4∠0 V. The source voltage V2 is





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  • By: guest on 02 Jun 2017 01.07 am
    IR = 2∠OA, I1 = 2∠-90° = -j 2A. Total current = 2 - j2. V2 = 2 (2 - j2) + 4∠0 = 8 - j4 volts.
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