1. If operator 'a' = 1 ∠120° then (1 + a) =





Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

  • By: guest on 02 Jun 2017 01.07 am
    Since 1 + a + a2 = 0, 1 + a = - a2.
Show Similar Question And Answers
QA->A man is facing East, then the turns left and goes 10 m, then turns right and goes 5 m, then goes 5 m to the South and from there 5 m to West. In which direction is he, from his original place ?....
QA->The political party registered by the Myanmar democratic leader Ang San Suu Kyi:....
QA->If the product of two numbers is 120 and the sum of their square is 289, then the sum of the two numbers is....
QA->Which port has become the first Indian port operator to achieve a new record of handling 200 million tonnes (MT) cargo movement?....
QA->Which telecom company has become the leading telecom operator by revenue market share (RMS) of 31.7 per cent in the April-June quarter?....
MCQ->A circuit is fed by two sources of the same frequency and values 100 ∠0° V and 20 ∠30°V. The current in a particular branch is 5 ∠19° A. If the magnitudes of the sources and changed to 200 ∠0° V and 40 ∠30° V, the current in that branch should be....
MCQ->A circuit is fed by two sources of different frequency and magnitudes 100 ∠0° V and 50 ∠30°V. The current in a particular branch is 10 ∠20° A. If the magnitudes of the sources are changed to 200 ∠0° V and 100 ∠0° V, the current in that branch should be....
MCQ->Assertion (A): Operator has a value 1 ∠ - 90° or 1 ∠ 90°.Reason (R): Operator 'a' has a value 1 ∠ 120°.

....
MCQ->If Va = 10 ∠0, Vb = 10 ∠ -120° and Vc = 10 ∠ -240°, then Va2 and Va0 are....
MCQ->In figure, Z1 = 200∠60° Ω, Z2 = 400∠ - 90° Ω, Z3 = 300∠0°. Then Z4 for bridge to be balanced is ....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution