1. An arbitrary signal m (t) has zero average value and it is bandlimited to 3.2 kHz. It is sampled at the rate of 8 K samples/S. The samples are passed through an ideal bandpass filter with centre frequency of 32 kHz and bandwidth of 6.4 kHz. The output of band pass filter is





Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

Show Similar Question And Answers
QA->The latitudes that pass through Sikkim also pass through which State?....
QA->The average monthly income of A and B is Rs. The average monthly income of B and C is Rs. 6250 and the average monthly income of A and C is Rs. What is the monthly income of A?....
QA->The average of 20 numbers is zero. Of them , at the most ,how many may be greater than zero?....
QA->The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero?....
QA->The average of 20 numbers is zero. Of them, How many of them may be greater than zero, at the most?....
MCQ->An arbitrary signal m (t) has zero average value and it is bandlimited to 3.2 kHz. It is sampled at the rate of 8 K samples/S. The samples are passed through an ideal bandpass filter with centre frequency of 32 kHz and bandwidth of 6.4 kHz. The output of band pass filter is....
MCQ->A 1 kHz sinusoidal signal is ideally sampled at 1500 samples/sec and the sampled signal is passed through an ideal low pass filter with cut off frequency 800 Hz. The output signal has the frequency.....
MCQ->A signal m(t) with bandwidth 500 Hz is first multiplied by a signal g(t) where The resulting signal is then passed through on ideal low pass filter with bandwidth 1 kHz. The output of the low pass filter would me....
MCQ->An audio signal of FM radio station is sampled at a rate of 15% above the Nyquist rate. Signal is sampled in 512 levels and bandwidth of the signal is 4 KHz. The minimum bandwidth required to transmit this signal will be....
MCQ->A signal m(t) with bandwidth 500 Hz is first multiplied by a signal g(t) where . The resulting signal is then passes through an ideal low pass filter with bandwidth 1 kHz the output of the low pass filter would be....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution