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1. Assertion (A): L[af1(t) + bf2(t)] = aF1(s) - bF2(s)Reason (R): Initial value theroem enables us to find the value of f(t) at t = 0 directly from F(s)





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  • By: guest on 02 Jun 2017 01.13 am
    £[af1(t) +bf2(t)] = aF1(s) + bF2(s) Hence A is wrong.
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